You are driving in your car at a constant speed. At the very top of a circular h

Question

You are driving in your car at a constant speed. At the very top of a circular hill with a radius of 30 m, you feel 1/5 as heavy as usual. What is your actual weight as you go over the top of the hill?

A(6/5) mg, upward

B(1/5) mg, downward

C(4/5) mg, downward

D(1/5) mg, upward mg, downward

What is the normal force acting on you as you go over the top of the hill?

A) mg, upward

B (1/5) mg, upward

C (4/5) mg, upward

D (6/5) mg, upward

What is the total force acting on you as you go over the top of the hill?

A (1/5) mg, upward

B (6/5) mg, upward

C (4/5) mg, downward

D mg, upward

E 0

What is your acceleration as you go over the top of the circular hill? 0

A v2/r, downward

B mg, upward

C v2/r, upward

D mg, downward

How fast are you moving at the top of the hill? (in m/s)

A: 0.0

B: 7.7

C: 15.3

D: 17.1

E: 18.8

Explanation / Answer

Question 1) since weight (W) = m*g acting downwards and

we feel 1/5 as heavy as usual

Actual weight = (1/5)*mg

Answer) option B)

Question 2) in this the normal force acts opposite to the weight in opposite direction(upward)

N = (1/5)mg

Answer) option B)

Question 3) answer) option E) 0

Reason : in the above situation, all the acting forces are balanced so the total acting force is 0

Question 4) answer ) option A) v^2/r downward

Reason : for the car to move in a circular motion, centripetal acceleration is necessary which is equal to v^2/r ( downward)

Question 5) answer) option B)

Using,

(1/5)*mg = mv^2/r

v^2/r = g/5

v^2 = 9.8*30/5

v = 7.7 m/s

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