In the gold medal ice hockey match. two players nA 76 kg mg = 87 kg collide on t

Question

In the gold medal ice hockey match. two players nA 76 kg mg = 87 kg collide on the ice and grab onto each other to keep from falling down. Before the collision. Skater A had a speed of 5.9 ms and an angle of 630. Similarly, skater B had a speed of 8.4 m/s and an angle of 143°. Determine the speed of the pair as they slide together after the collision Answer Incorrect, tries 1/4. Submit All Answers Last Answer: 4.84 m/s 20. [5pt] Determine the angle of the pair after the collision. Answer Submit All Answers

Explanation / Answer

by conservation of momentum

initial horizontal momentum = final horizontal momentum

76 * 5.9 * cos(63) + 87 * 8.4 * cos(143) = (76 + 87) * v * cos(theta) -------- (1)

initial vertical momentum = final vertical momentum

76 * 5.9 * sin(63) + 87 * 8.4 * sin(143) = (76 + 87) * v * sin(theta) ----------- (2)

on solving 1 and 2 we'll get

v = 5.652 m/s

theta = 114.4 degree

speed of the pair = 5.652 m/s

angle = 114.4 degree

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