1x ull 3%a1 1:21 PM https://session.masterin L| Problem 7.33 - Enhanced - with F

Question

1x ull 3%a1 1:21 PM https://session.masterin L| Problem 7.33 - Enhanced - with Feedback An athlete at the gym holds a 2.5 steel ball in his hand His arm is 70... long and has a mass of 4.0 You may want to review (pages 204-205) Part A What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Express your answer to two significant figures and include the appropriate units Submit My Answers Give Up Part B What is the magnitude of the torque about his shoulder if he holds his arm straight, but 30 below horizontal? Express your answer to two significant figures and include the appropriate units Submit My Answers Give Up

Explanation / Answer

part A)

magnitude of the torque = 2.5 * 9.8 * 0.70 + 4 * 9.8 * 0.70/2

magnitude of the torque = 30.9 N.m

the magnitude of the torque is 30.9 N.m

part B)

when the shoulder is 30 degree below

magnitude of the torque = 2.5 * 9.8 * 0.70 * cos(30 degree) + 4 * 9.8 * 0.70/2 * cos(30 degree)

magnitude of the torque = 26.8 N.m

the magnitude of the torque is 26.8 N.m

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.