Problem 22.030 (modified) A conducting coil of 1580 turns is connected to a galv

Question

Problem 22.030 (modified) A conducting coil of 1580 turns is connected to a galvanometer, and the total resistance of the circuit is 45.0 . The area of each turn is 4.00 × 10-4 m2. This coil is moved from a region where the magnetic field is zero into a region where it is nonzero and pointed up, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be 7.88 × 10-3 C. (a) What is the magnitude of the magnetic field? (b) Is the current induced flowing clockwise or counterclockwise? Why? Solution:

Explanation / Answer

a)

Use the equation emf = N(/t)

Since emf is voltage you can rewrite V = N(/t)

Since V=IR by Ohms law you get IR = N(/t)

Then, since I = (Q/t) you get (Q/t)R = N(/t)

Thus your t's cancel and you get QR = N()

Rewrite this as QR = N(BA)

=> B = QR/NA

Now plug in you numbers:

B = (7.88e-3)(45)/(1580)(4e-4)

= 0.561 T

b) Counterclockwise, by right hand curl rule.

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