tr The Expert TAI Human- e An Object 4 Cm Tall kpix x Secure https://u ommon/Tak

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tr The Expert TAI Human- e An Object 4 Cm Tall kpix x Secure https://u ommon/TakeTutorialAssignment.aspx Home Student: klcarterou.edu My Account Log Out Class Management Help Homework 7 Begin Date: 10/11/2017 12:00:00 AM- -Due Date: 10/23/2017 11:59:00 PM End Date: 10/23/2017 11:59:00 PM (496) Problem 18: An object of height 2.7 cm is placed 25 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 13 cm from it, there is a converging lens of the same focal length. ent Status here for ed view 50% Part (a) Find the location of the final image. in centimeters beyond the converging lens. Grade Summary Deductions Potential 0% 100% Status Completed Completed Completed Completed Completed Completed Completed Completed Completed Completed Completed Completed Completed Completed sin) cosO asin0 tan() | acosO Submissions Attempts remaining: 4 (0% per attempt) detailed view cotan) 4 5 6 atan acotan sinh0 0% 0% 0% coshO tanh cotanh(0 Degrees Radians Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedback. 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object. 11:22 AM Type here to search 10/23/2017

Explanation / Answer

let's find the position of the image from the diverging lens,

u = 25 cm, f = - 17 m

1/v= 1/f - 1/u = -1/17 - 1/25

v = ( 25x 17) /(-42) =-10.11 cm apprx

object distance for converging lens = 13 cm + 10.11 = + 23.11 cm

u = +23.11 cm, f=+ 17 cm

1/v= 1/f - 1/u = 1/17 - 1/23.11= ( 6.11) / ( 23.11 x 17)

v = 64. 3 cm apprx from converging lens and on the right hand side of lens,

m = m1 x m2 = ( -10.11/ 25 ) (64.3 / 23.11) =-1.125

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