98 N 147 N 147 N 98 N a) 140 N b) 147N c) 140 N d) 147 N A 6.00-kg block and an
ID: 1785213 • Letter: 9
Question
98 N 147 N 147 N 98 N a) 140 N b) 147N c) 140 N d) 147 N A 6.00-kg block and an 8.00-kg block are connected as shown When released, the 6.00-kg block accelerates downward and the 8.00-kg block accelerates to the right. After each block has moved 2.00 cm, the total work done on the 8.00-kg block 2. a) is less than the total work done on the 6.00-kg block b) is the same as the total work done on the 6.00-kg block c) is greater than the total work done on the 6.00-kg block d) not enough information given to decideExplanation / Answer
Since both masses are connected by a single string both have equal acceleration = a
Both traveled with same distance = d
Work done on mass m1(8.00kg)= W1= Net force on m1*distance traveled = F1*d = m1*a*d -----------(1)
Work done on mass m2(6.00kg)= W2 = Net force on m2*distance traveled = F2*d = m2*a*d -----------(2)
m1>m2,
Comparing eqn (1) and (2),
W1>W2
Thus total work done on the 8.00-kg block is greater than the total work done on the 6.00-kg block.
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