Exercise 5 (16 points) of polyvinyl chloride (PVC) with an edge length of 2 em h

Question

Exercise 5 (16 points) of polyvinyl chloride (PVC) with an edge length of 2 em has an initial temperature of 100° C. The PCV cube is placed into 500 ml of water at 20° C. (a) What is the final temperature of the mixture? (The density of water is 1 g/cm the density of PVC is 1.41 g/cm3, the specific heat capacity of water is 1 cal/gC and the specific heat capacity of PCV is 0.9 cal/g C'). (8 points) Note: I did not give you the masses of the PVC or the water. Can you determine the masses of the PVC and the water from the other information that I gave you? PvC

Explanation / Answer

Mass PVC = volume x density = 23 * 1.41 = 11.28 gm
Mass of water = 500*1 = 500 gm
Let final tempreture = T deg C
Heat energy given by PVC = m c ( change in tempreture) = 11.28*0.9 ( 100-T) = 10.15(100-T)
Heat energy taken by water = 500*1 ( T - 20)
Energy given by PVC = energy taken by water
10.15(100-T) = 500 ( T-20)
T = 21.6 degC

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