roblem 8.27- Enhanced-with Feedback Part A A0.26-kg rock is thrown vertically up

Question

roblem 8.27- Enhanced-with Feedback Part A A0.26-kg rock is thrown vertically upward from the top of a cliff that is 31 m high. When it hits the ground at the base of the cif, the rock has a speed of 32 m/s. You may want to review (Mpa23,241! Assuming that air resistance can be ignored find the iniial speed of the rock Express your answer using two significant figures m/s Submit My Answers Give Up Incorrect; Try Again; 8 attempts remaining Part B Find the greatest height of the rock as measured from the base of the ckt Express your answer using two significant figures. My Answers Give Up 4 NA

Explanation / Answer

a) initial mechanical energy = final mechanical energy

m g h + 1/2 m vi2 = 0 + 1/2 m vf2

vi = sqrt [vf2 - 2 g h]

= sqrt [322 - (2 * 9.8 * 31)]

= 20.4 m/s

b) h = v2 / 2 g

= 20.42 / (2 * 9.8) = 21.23 m

maximum height = 31 + 21.23

= 52.23 m

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