Problem: lomework x A Block With Mass M1-2 x >C Secure! https://wwww.flipitphysi
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Problem: lomework x A Block With Mass M1-2 x >C Secure! https://wwww.flipitphysics.com/Course/ViewProblem?unitltemID-3079008&enrollment;!D-263672 SoundCloud N NetflixHBO Now Uverse Rlacebook D Enterprise Google Calenda Curmpass 2 | Moodle | MCB 252 e Lun Csua afluitphysics » Other bookmarks Problem 46 tandard Fxrrier Multiple Choice 8 A block with mass mi 2.60 kg rests on a frictionless table. It is connected with a light string over a pulley to a hanging block of mass m2=4.60 kg. The pulley is a uniform disk with a radius of 4.60 cm and a mass of 0.530 kg lthe figure below) Standard Lxercise Problem 20 /n tandard Exercise Problem 22 Standard Exorrisc Problem 23 i1 tadard Exercise Problem 45 1) Calculate the acceleration of each block. (Express your answer to three significant figures.) tandard Fxrsrisr Problem 46 m/s Submit 6.26 You currently have 5 submissions for this question. Only 10 submission are allowed You can make 5 more submissions for this question. lanad Exercise Problem 47 Your submissions: 6.26 Computed value: 6.26 Feedback: Right answer l tandard Fxrrrier Cumulative Problem 18 Submitted: Tuesday, October 24 at 10:39 PM 2) Calculate the tension in the -direction (horizontal part of string). (Express your answer to three significant figures.) 16.3 N Submit You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. 10-53 PM Ask me anything 10/24/2017Explanation / Answer
on m2:
4.60 g - T2 = 4.60a ........(i)
on m1:
T1 = 2.60 a ..... (ii)
on pulley:
torque = I alpha
r (T2 - T1) = (m r^2 / 2) (a/r)
T2 - T1 = 0.265 a ..... (iii)
(i) + (ii) +(iii) =>
4.60 x 9.81 = (4.60 + 2.60 + 0.265) a
a = 6.045 m/s^2
1) a = 6.04 m/s^2
2) T1 = 2.60 a = 15.7 N
3) T2 = 4.60 ( g - a) = 17.3 N
4) d = v0 t + a t^2 /2
2.75 = 0 + 6.04 t^2 /2
t = 0.954 sec
5) v = v0 + a t = 6.04 x 0.954 = 5.76 m/s
w = v / r = 125.3 rad/s
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