Question 1 A 58.0 kg snowboarder heads down a 21.5° hill that has a height of 77

Question

Question 1

A 58.0 kg snowboarder heads down a 21.5° hill that has a height of 77.9 m. If the hill is assumed to be frictionless and there is horizontal wind with a force of 74.8 N acting against the snowboarder, find the speed of the snowboarder as they reach the bottom of the hill using work and energy.

Question 2

In the figured provided, a 93.0 kg boy compresses a spring by 0.450 m and slides down a frictionless slide. The slide leads into a 30° ramp that has a coefficient of kinetic friction of 0.280 with the boy. If the spring constant in the spring is 74500 N/m and the slide has a height of 48.0 m, what distance up the ramp will the boy get before stopping?

Explanation / Answer

1] Work done by all forces = change in Kinetic energy

mgh - Fwind * d = 0.5 mv^2 where d = h/tan theta

58*9.8*77.9 - 74.8*77.9/ tan 21.5 degree = 0.5*58*v^2

  29486 = 29 v^2

v = sqrt(29486/29)

= 31.9 m/s answer

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