1)What is the distance the center of mass is from the origin? 2)What is the x-co

Question

1)What is the distance the center of mass is from the origin?

2)What is the x-component of the velocity of the center of mass?

3)What is the y-component of the velocity of the center of mass?

Friday, November 17 5:34 PM tyler wes FlipltPhysics macmillan learning Physics 2130-006 Fall 2017 University of Toledo Unit 21: Pre-Lecture/ CheckpointHomework F Homework: 2130 Exam 2 Extra Credit Fall 2017 Deadline: 100% until Friday, November 17 at 11:59 PM System of Particles 2 Four particles are in a 2-D plane with masses, x and y positions, and x and y velocities as given in the table below: 1 9.2 kg -2.7 m 4.5 m 3 m/s 4.2 m/s 47.5 kg 5.4 m 2.6 m -4.1 m/s -2.9 m/ 1) What is the distance the center of mass is from the origin? m Submit currently have 0 submissions for this question. Only 2 submission are allowed You can make 2 more submissions for this question. search 3 4 5 6 8 9 3

Explanation / Answer

Xcm = ((m1*x1) + (m2*x2)+(m3*x3)+(m4*x4))/(m1+m2+m3+m4)

Xcm = (-(9.2*2.7) - (8*3.5) + (8.8*4.6) + (7.5*5.4))/(9.2+8+8.8+7.5)

Xcm = 0.84 m

Ycm = ((m1*y1) + (m2*y2)+(m3*y3)+(m4*y4))/(m1+m2+m3+m4)

Ycm = (-(9.2*4.5) + (8*3.7) - (8.8*5.4) + (7.5*2.6))/(9.2+8+8.8+7.5)

Ycm = -1.19 m

(1)

distance of center of mass from origin = sqrt(Xcm^2+Ycm^2) = 1.46 m

(2)

Vx = ((m1*vx1) + (m2*vx2)+(m3*vx3)+(m4*vx4))/(m1+m2+m3+m4)

Vx = ((9.2*3) - (8*5.2) - (8.8*5.9) - (7.5*4.1))/(9.2+8+8.8+7.5)

Vx = -2.88 m

part(3)

Vy = ((m1*vy1) + (m2*vy2)+(m3*vy3)+(m4*vy4))/(m1+m2+m3+m4)

Vy = ((9.2*4.2) + (8*5) + (8.8*2.1) - (7.5*2.9))/(9.2+8+8.8+7.5)

Vy = 2.25 m

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