A medical cyclotron used in the production of medical isotopes accelerates proto

Question

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.4 T .

Part A

What is the diameter of the largest orbit, just before the protons exit the cyclotron?

Express your answer with the appropriate units.

SubmitMy AnswersGive Up

Part B

A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

SubmitMy AnswersGive Up

Explanation / Answer

A] speed v = sqrt(2E/m) = sqrt(2*6.5e6*1.6e-19/1.673e-27) = 35260112 m/s

now diameter of orbit in magnetic field = 2* mv/qB = 2*1.673e-27*35260112/(1.6e-19*1.4)

= 0.5267 m

B] number of orbits = vt/(2pi r) = 35260112*1e-3/(2pi*0.5267/2) = 21309 orbits

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.