3 MasteringPhysics: Nov 13 On-Line HW Chs 9, 10- Google Chrome -Secure https/ses
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3 MasteringPhysics: Nov 13 On-Line HW Chs 9, 10- Google Chrome -Secure https/session master ingphysics.com/myct itemView?assignmentProblemID=87594848 Nov 13 On-Line HW Chs 9. 10 Fluid P Physics Pressure in a U-Tube Fluid Pressure in a U-Tube A U-tube is filled with water, and the two arms are Part A negligible mass, are watertight, and can freely slide up and down the tube capped (Figure 1) The tube is cylindrical, and the right arm has twice the radius of the left arm. The caps have A one-inch depth of sand is poured onto the cap on each arm. (Figure 2) After the caps have moved (if necessary) to reestablish equilibrium, is the right cap higher, lower, or the same height as the left cap? Hints O lower the same height Submit My Answers Give Up Part B This question will be shown after you complete previous question/s) Part c This question will be shown after you s question s)Explanation / Answer
Since figure 2 is not given, it is being assumed from description that sand column is 1 inch high above caps. Also, initially the caps are at same level because pressure above them is the same as that of atmospheric pressure.
Now, let density of sand is d, radius of left and right arm are r and 2r.
Then weight of sand on left arm= w= acceleration due to gravity *volume of sand column* density of sand= g* d* pi*r^2*h {where h=1 inch}
Area of left cap =a = pi*r^2
Pressure on left cap due to this weight= p= weight/area = w/a
Now, similarity, weight of sand on right arm= W= acceleration due to gravity *volume of sand column* density of sand= g* d* pi*(2r)^2*h {where h=1 inch}= 4w
Area of right cap =A = pi*(2r)^2= 4a
Pressure on right cap due to this weight= P= weight/area = W/A= 4w/4a= w/a= p
So, P= p
Since before putting sand the pressure above both right and left cap is same as that of atmospheric pressure, and after putting sand again the pressure on the caps remain same, hence the right cap is the same height as the left cap.
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