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Safarl File Edit View History Bookmarks Window Help 64% Sun 12:31 PM Q ! Assignment Submission For this assignment, you submit answers by question parts. The number of submissions remaining for euch question Assignment Scoring Your best submission for each question part is used for your score. part only changes if you submit or 341 points Previous Answers M4 10.7.022 nucleus contains 108 nucleons (47 protons and 61 neutrons) packed tightly against each other. A single nucleon (proton or neutron) has a radius of about 1 x 10-15 m. Remember that the volume of a sphere is A (a) Calculate the approximate radius of the silver nucleus. 4.780-15 m (b) Calculate the approximate radius of the alpha particle, which consists of 4 nucleons, 2 protons and 2 neutrons 4.55e-12 xnm (c) What kinetic energy must alpha particles have in order to make contact with a silver nucleus? 17.05 x Mev Rutherford correctly predicted the angular distribution for 10-MeV (kinetic energy) alpha particles colliding with gold nuclei. He was lucky: if the alpha partide had been able to touch the gold nucleus, the strong interaction would have been involved and the angular distribution would have deviated from that predicted by Rutherford, which was based solely on electric interactions. Additional Materials Section 10.7

Explanation / Answer

V_nucleon = 4 pi r^3 / 3

(A) silver has 108 nucleons.

V = 108 (4 pi r^3 / 3) = 4 pi R^3 / 3

R = (108)^(1/3) (1 x 10^-15)

R = 4.76 x 10^-15 m

(B) for alpha, nucleons = 4

V = 4 (4 pi r^3 / 3) = 4 pi R^3 / 3

R = 1.587 x 10^-15 m

(C) PE at the time of contact.

PE = k q1 q2 / d

PE = (9 x 10^9) (47 x 1.6 x 10^-19) (2 x 1.6 x 10^-19) / (1.587 + 4.76)x10^-15

PE = 3.412 x 10^-12 J

so KE = 3.412 x 10^-12 J

KE = (3.412 x 10^-12)/(1.6 x 10^-19) = 21.3 x 10^6 eV  

KE = 21.3 MeV

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