oO AT&T; LTE 2:18 PM loncapa2.physics.sc.edu Cameron Chambers (Sbudensectin017 F

Question

oO AT&T; LTE 2:18 PM loncapa2.physics.sc.edu Cameron Chambers (Sbudensectin017 Fall, PHYS 202 (P e Messages Courses Help Logout Main Menu l W Bookmark Evaluate Communicate Print nlnfo (hrw8c29p68) Each of two long straight parallel wires 11 cm apart carries a current of 75 A. The figure shows a cross section, with the wires running perpendicular to the page and point P lying on the perpendicular bisector of the line between the wires. Find the magnitude and direction of the magnetic field at P when the current in the left-hand wire is out of the page and the current in the right-hand wire is also out of the page Wire 1 Wre 2 What is the magnitude of B? What is the value of Bx? ries 0/10 What is the value of By? What is the value of Bz tries 0/10 Find the magnitude and direction of the magnetic field at P when the current in the left- hand wire is out of the page and the current in the right-hand wire is into the page. What is the of B? of 8p What is the value of Bx? What is the value of By? tries 0/10 What is the value of Bz? is discussion is closed Sand Feedback

Explanation / Answer

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for parallel wires with same magnitude of currents and in same direction

these forms St wires and magnetic field is given by B = uoI/2pir

here for land hand wire

I = 75 A

r = 11/2 = 5.5 cm or 0.055 m

uo is permeability constant = (4pi *10^-7) H/m

So B1 due to left wire = B1 = (4pi *10^-7 * 75)/(2pi* 0.055)

B1 = 2.7 *10^-4 Tesla

By Amperes rule, this B1 is directed anti clock wise at point P ( along Z in upwards path)

and B2 due to Right wire is also same B2 = 2.7 *10^-4 tesLa

Direction of B2 = along -Z axis

so

Bnet = B1 + B2

Bnet = B1 +(-B2) as both are same magnitudes
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Bnet = 0
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thus Bx = 0 , BY = 0 and Bz = 0
==================================================

if left wire is out of page , B1 = 2.7 *10^-4 Tesla , upwards at D

right is into page, B2 = 2.7 *10^-4 tesla also upwards at D

so

Bnet = B1 + B2

Bnet = 2.7 *10^-4 + 2.7 *10^-4
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BNet = 5.4 *10^-4 tesla

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thus Bx = 0 , By = 0 and Bz = 5.4 *10^-4 tesla
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