bullet? (specific heat of lead-0.0305 kcal/kg°C, 1 kcal = 4 186 J) ( 0,5 78.3 oC

Question

bullet? (specific heat of lead-0.0305 kcal/kg°C, 1 kcal = 4 186 J) ( 0,5 78.3 oC DUllaMt heat energy generated remains with the bullet, what is the increase in temperaturg of th o Speed of 200 m/s when it embeds in a wood post, If we assume that half of b. 157 °C s700- 0-13 X10 One gallon of water has a mass of approximately 3.8 kg c. 313 °C d. 39.2°C swimming pool heater has to be able to raise the temperature of the 50 000 gallons of water .. How many kilowatt-hours of energy are required? nd the specific heat of water is 4,186 J/kg °C.) 8E+2 k Wh SE+3 kWh IE+2 kWh 5E+4 kWh E+2 kWh 2 A solar heated house loses about 5.5 x 10 cal through its outer surfaces on a typical 24-h winter day. What mass of storage rock is needed to provide this amount of heat if it is brought up to initial temperature of 58 by the solar collectors and the house is maintained at 23°C? (Specific heat of rock is 0.21 cal/g-C) a. 1.4E+3 kg 4 kg c. 7.5E+3 k d. 7.5E+2 kg

Explanation / Answer

First problem -

Mass of water = m = 50000 gallons = 50000 x 3.8 kg

specific heat of water = 4186 J/Kg.C

delta T = 12 deg C

So quantity of energy required to raise the temperature of swimming pool water -

Q = m*s*delta T = 50000 x 3.8 x 4186 x 12 = 9544080000 Joules = 9544080000 / (1000 x 3600) kWh

= 2651 kWh = 2.65 x 10^3 kWh

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