QUESTION 12 2 points What is the orbital speed of a satelite in a circular orbit
ID: 1787588 • Letter: Q
Question
QUESTION 12 2 points What is the orbital speed of a satelite in a circular orbit at 7,060 kilometers above the Earth surface? Express your answer in km/s and round it to two decimals. Earth's mean radius is RE 6.37 x106 m; Earth's mass is ME = 5.97×1024kg. QUESTION 13 2 points s What is the orbital period of a satelite in a circular orbit at 2,753 kilometers above the Earth surface? Express your answer in minutes (enter 'min" for minutes) and round it to the nearest integer. Earth's mean radius is RE = 6.37x106 m; Earth's mass is ME" 5.97x1 024kg. QUESTION 14 2 points S What is the escape velocity from Earth's gravity for a spacecraft launched from the orbit at an altitude of 15,583 kilometers above the Earth surface? Earth's mean radius is RE 6.37 x106m; Earths mass is ME = 5.97×1024kg. Express your answer in km/s and round it to two decimals. QUESTION 15 2 points Sa What is the escape velocity from Sun's gravity for a spacecraft with mass 10,731 kilograms launched from a distance equal to the Jupiter's average orbital distance from the Sun i.e. 5.2 AU (1 AU = 1.5x 108 km)? Msun 1.99 x 1030 kg. Express your answer in km/s and round it to two decimals.Explanation / Answer
Q12) Given,
h = 7060 km ; Re = 6.37 x 10^6 m ; Me = 5.97 x 10^24 kg
We know that the orbital speed is given by:
v = sqrt (GM/R)
R = h + Re = 7.060 x 10^6 + 6.37 x 10^6 = 1.343 x 10^7 m
v = sqrt (6.67 x 10^-11 x 5.97 x 10^24/(1.343 x 10^7)) = 5445.18 m/s
Hence, v = 5.445 km/s
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