D) 16 V.4V since the rate of change of the current is not given Open ended (10 p

Question

D) 16 V.4V since the rate of change of the current is not given Open ended (10 points each) 1. mass o#6 An alpha particle (An alpha particle has a charge of ravels at a 3.2m 10-vs C and un having a length of 25cm and a diameter of S cm carries a current of 3.OA).T wee and B is 52. What is the magnitude of (a) the force F w scting on the (10lcity of magnitude 550 m/s through a uniform magnetic field B within a of (a) the force Fa acting on the particle due to the field and (b) the acceleration of the particle due to Fu? (c) Does the speed ase, or remain the same? (d) What is the trajectory of the particle motion?

Explanation / Answer

Magnetic field due to solenoid is given by

B=uoNI/L =(4pi*10-7)*100*3/0.25=1.508*10-3T

a)

Magnetic force

FB=qVBsin(o) =(3.2*10-19)(1.508*10-3)(550)sin52=2.09*10-19 N

b)

acceleration

a=F/m =(2.09*10-19)/(6.6*10-27)

a=3.17*107 m/s2

c)

stays the same

d)

r=mv/qB =(6.6*10-27)(550)/(1.6*10-19)(1.508*10-3)

r=0.015 m

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