( 25 % ) Problem 2: Suppose you exert a force of 175 N tangential to the outer e
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Question
( 25 % ) Problem 2: Suppose you exert a force of 175 N tangential to the outer edge of a / 26 mi radnis 745-kg grindstone (which is a solid disk). 33% Part what is the torque r, in newton meters, you are exertin on the grindstone relative to the center of mass ofthe grindstone a Grade Summary Deductions Potest.al 100% Submissions Attempts remaining sinO cotanO asinO acos0 at acotan) sinho coshO tanhO cotamho etailed view e Degrees Radians NO Submit Feedback: deduction per feedback Hints: 4% deduction per hint Hints remaining:- 33% Part (b) what is the angular acceleration of the grindstone a-in radians per square econd, if there is an opposing 21 N exerted 0.45 m from the axis? fictional force of 33% Part (c) What is the angular acceleration of the grindstone af in radians per square sExplanation / Answer
(i) torque = F * r since the force is perpendicular to the radius
= 175N * 1.26m = 220.5 N·m
(ii) also = I * where I is the moment of inertia
For a uniform disk, I = ½mr² = ½ * 74.5kg * (1.26m)² = 59.14 kg·m²
so
220.5 N·m = 59.14 kg·m² *
= 3.73 rad/s²
(iii) Now net torque ' = 220.5N·m - 21N * 0.45m = 211.05 N·m, and so
211.05 N·m = 59.14 kg·m² * '
' = 3.57 rad/s²
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