9.5x10\' kg and velocity -270,000i m\'s collides tangentially with the planet at
ID: 1788214 • Letter: 9
Question
9.5x10' kg and velocity -270,000i m's collides tangentially with the planet at its equator, ( the point (0, 5.42×106 m,0)) and becomes lodged in the planet's crust. Calculate the angular momentum of the planet (with asteroid) and the angular velocity, about the center of the plane immediately after the collision. (Assume the planet has a uniform density before the collision 2. A person of mass 65 kg stands at the edge of a rotatable disc, initially at rest, of mass 82 k and radius 1.8 m. She fires a bullet of mass 4.7 g at a speed of 470 m/s in the direction shown How fast do the person and the disc start to rotate? : 30% 3. An object experiences a force given by F = 2yi_ 0.5x2j. It moves along a path given by r = (3-1)^+ (42-2)i.Explanation / Answer
2. Applying anular momentum conservation,
Li = Lf
0 = (0.0047 x 470 x 1.8 x cos30) - ( (65 x 1.8^2) + (82 x 1.8^2 / 2)) w
3.44 = 343.44 w
w = 0.01 rad/s
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