« previous | 4 of 21 I next>» Problem 11.14 Part A What is the angular accelerat
ID: 1788233 • Letter: #
Question
« previous | 4 of 21 I next>» Problem 11.14 Part A What is the angular acceleration of the rod after it is released? A 0.180-kg wooden rod is 1.30 m long and pivots at one end. It is held horizontally and then released Express your answer to three significant figures and include appropriate units alueUnits Submit My Answers Give Up Part B What is the linear acceleration of a spot on the rod that is 1.08 m from the axis of rotation? Express your answer to three significant figures and include appropriate units alueUnits Submit My Answers Give Up Part C At what location along the rod should a die be placed so that the die just begins to separate from the rod as it falls? Express your answer to three significant figures and include appropriate units Value UnitsExplanation / Answer
a) T = I * alpha
T = r * F
alpha = r F / I
I = mL2/3 = (0.18 * 1.32) /3
alpha = ((1.3/2) * 0.18 * 9.8) / (0.18 * 1.32) /3 )
angular acceleration = 11.31 rad/s
b) linear acceleration = r * alpha = 1.08 * 11.31
linear acceleration = 12.21 m/s2
c) g = r alpha
r = 9.8 / 11.31 = 0.866 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.