1. Suppose the tube you used emitted protons instead of electrons. How would thi

Question

1. Suppose the tube you used emitted protons instead of electrons. How would this change the experiment? Would the experiment be easier or more difficult to perform? 2. In 1909, the American physicist Robert Millikan measured the elementary unit of charge,"e, to be 1.6 x 1019 Coulomb. Using this value and your value of e/m from the experiment, what va! e do you calculate for the mass of an electror 3. How does your determined value of the mass of the electron compare with its theoretical value Kg? -31 of "m" given in the textbook as 9.11 x 10

Explanation / Answer

1)If an electron will be taken instead of proton then the magnetic force on charge which is given by:

F = q v B sin(theta)

will remain same in the magnitude but the direction will be apposite to that of a positive charge(proton).

Since an electron is lighter than a proton the e/m will be increased.

2)e = 1.6 x 10^-19 C ; e/m = 2.4 x 10^11 C/kg

m = 1.6 x 10^-19/2.4 x 10^11 = 6.67 x 10^-31

Hence, using the value of e/m we got,

3)m = 6.67 x 10^-31 kg which is different than theoritical value of m = 9.1 x 10^-31 kg.

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