In Figure a string 1 has linear density 1 and string 2 has linear density 2 They

Question

In Figure a string 1 has linear density 1 and string 2 has linear density 2 They are under tension due to the hanging block of mass M. Calculate the wave speed on a) string 1 and (b) string 2 in terms of the given variables and g. (Hint: When a string loops halfway around a pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M1 M2 M) and the apparatus is rearranged as shown in Figure (b). Find (e) M1 and (d) M2 such that the wave speeds in the two strings are equal. Make sure your answers to parts (e) and (d) are in terms of the given variables only (the variables M2 and Mi must not appear in part (c) and (d), respectively.) String 1 String 2 Knot 2 String 1 String

Explanation / Answer

d1=u1

d2=u2

m=M

T=mg/2

in each string v=squr(T/d)=squr(mg/(2d))

plug d1 and d2 to find v1 and v2

v1=option (A)

v2=option(B)

now,

for option(C)

m1=md2/(d1+d2)

md1/(d1+d2)

(D) m2=md2/(d1+d2).

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