Below is the data tables and so background information on the experiment... than

Question

Below is the data tables and so background information on the experiment... thanks

1. Find the percent error between your experimental value of the slope of Ihv vs. Iu from your calculator's linear regression calculation and the theoretical value of-1.00 2. Why do the values of both u and v differ from the values of u' and v' as measured from the mount positions? 3. What is the physical significance of the negative sign in the magnification formula? 4. How would one determine that the image is inverted in this experiment? 5. Determine the percent error between the theoretical magnification, Mnvu, and the experimental magnification, Mey, 3, for two sets of values in the data table. Use algebra and the substitution of terms to show that: 6. 2 2b This should not be shown by using experimental data which you collected. Question 6 does not have any calculations

Explanation / Answer

1. from the given data

slope of 1/v vs 1/u graph = -1.00462

theoretical slope = -1

%error = (1.00462 - 1)*100 = 0.462%

2. the values of both v', u' differ by some value from the values of v, u because of the zero erorr introduced in the hardware by the mark on the mount and actual placement of the object and the imege

3. -ve sign in the magnification formula tells us that the final image is inverted

4. on this experiment, if the image is real, on the other side of the lens we can assume that the image is inverted

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