PROBLEM 5 -8 points [2 points] (a) You put some water in a glass, and then drop
ID: 1789132 • Letter: P
Question
PROBLEM 5 -8 points [2 points] (a) You put some water in a glass, and then drop in an ice cube to cool the water. The ice cube floats at the surface of the water, as usual. As the ice melts, what happens to the water level in the glass? Neglect any change in density of the liquid. The water level (the level of the surface) rises [ ] stays the same [ ] drops Briefly explain [2 points] (b) The question above relates to why, as far as sea level rise because of global warming is concerned, we're a lot more worried about ice that is currently on land, as opposed to ice that is already floating on water (such as the ice in the Arctic). The ice sheet on Greenland has a volume of approximately 3.0 million cubic km. The surface area of Earth is about 5.0 x 1014 m2, and 70% of the surface is covered by oceans. Use these numbers to estimate the average amount of sea level rise that would happen if all the ice in Greenland melted and ran off into the ocean. (You can assume that the ice, after it melts, has a volume of 90% of what it had in solid form.) [2 points] (c) Assume the initial temperature of the Greenland ice is Tice-20 °C. How much energy is required to melt all the Greenland ice? Use a specific heat of 2 kJ/(kg °C) for ice and approximate the latent heat of fusion as 300 kJ/(kg) [2 points] (d) During the summer, sunlight and warm air transfers energy to the Greenland ice sheet at the rate of approximately 2 x 10 W. (Assume this happens for three months per vear.) If this energy warms and melts the surface ice, what is the sea-level rise from one summer of melting? Assume all the melted ice flows into the ocean (fortunately, that's not what happens)Explanation / Answer
(A) ice cube will displace water equal to its weight.
and after it converts it converts into water of same weight.
so final level will remain same.
Ans: Stays the same.
(b) volume of water that generated from melting of ice
= 0.90 x 3 x 10^6 km^3
= 2.7 x 10^15 m^3
surface area of ocean = 0.70 x 5 x 10^14
= 3.5 x 10^14 m^2
raise in height = 2.7 x 10^15 / (3.5 x 10^14)
= 7.71 m .......Ans
(C) Q = m Lf + m C delta(T)
Q = (2.7x 10^15 x 10^3 kg) (2 kJ / kG degC) (20) + (2.7 x 10^15 x 10^3 x 300)
Q = 9.18 x 10^20 kJ
(d) Q = (2 x 10^14) (3 x 30 x 24 x 3600 s)
Q = 1.5552 x 10^21 J = 1.5552 x 10^18 kJ
Level increase = (7.71) ( 1.5552 x 10^18 / 9.18 x 10^20 )
= 0.013 m Or 1.3 cm
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