48 (5 points). (a) Calculate the equilibrium frequency with mutation rate, x 10-

Question

48 (5 points). (a) Calculate the equilibrium frequency with mutation rate, x 10-6 mutations generation and back mutation, v 3.1 x 1o 8 mutations/generation. disease similar to a is an autosomal recessive disease. In a population, disease. What is the frequency of the recessive 1 in 18.000 infants has this allele t assuming random mating? The expected frequency of (c) Can a mutation rate of 4.4 x 107 mutations/generation after 125 generations explain the frequency recessive allele t of the population part 48(b)? Assume back rate of approximately zero, and starting frequency of the dominant Calculate the allelic frequency of dominant allele T after 125 generations. What would the frequency of recessive allele t be with p125? p125 q125 Can the mutation rate after 125 generations explain the allelic frequency of the population?

Explanation / Answer

Calculate the equilibrium frequency of muatation rate = 7.8x 10^-6 mutations/ generation and back mutation v= 3.1 x106-8 mutations/ generation

u = rate of forward mutation = 7.8 * 10^-6,

let v= rate of back-mutation = 3.10 * 10^-8.

Let p be the frequency of A and q be the frequency of a.

At equilibrium

p = v/(u+v),

and

q = 1-p. So

q = 1- [3.10 * 10^-8 /(7.8 * 10^-6 + 3.10 * 10^-8)] = 0.0039.

p=1-q=1-0.0039. 0.996

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Question 49

HH

Hh

hh

observed

105

50

45

200

D

H

R

105/200=0.525

50/200=0.250

45/200=0.225

Frequency of H allele = D +H/2

= 0.525 +0.250/2= 0.65--------------ANSWER

Frequency of h allele =R +H/2

= 0.225 +0.250/2= 0.35-------ANSWER

HH

Hh

hh

observed

105

50

45

200

D

H

R

105/200=0.525

50/200=0.250

45/200=0.225

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