The famous World War II Boeing B-29 Superfortress bomber could fly non stop for

Question

The famous World War II Boeing B-29 Superfortress bomber could fly non stop for 14 hours without refueling. Its 4 huge gasoline powered engines produced 8000 total Horsepower and had a real life efficiency of 20% for converting fuel into p for a 14 mechanical power output. Assuming the engines would produce hour mission, calculate the number of gallons of gasoline the B-29 would need to carry for a 14 hour mission. Useful conversions: 1 Hp = 746 W, burning 1 gallon of gasoline produces 120,000 BTU of heat energy, 1 BTU = 1053 J, 1 Hp-746 w

Explanation / Answer

mechanical work = power x time = 8000 x 746 x 14 x 3600 J

now as only 20% efficient

energy used = (8000 x 746 x 14 x 3600)/0.2 J

1 gallon produces energy = 120000 x 1053 J

now number of gasoline gallons used = (8000 x 746 x 14 x 3600/0.2)/(120000 x 1053) = 11901.9943

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