(17%) Problem 3: A car is driving along a circular track of diameter d = 0.55 km

Question

(17%) Problem 3: A car is driving along a circular track of diameter d = 0.55 km at a constant speed of v = 25.5 m/s. Otheexpertta.com 25% Part (a) Write an expression for the magnitude of the acceleration a of the car in terms of the given parameters Grade Summary a= 100% Attempts remaining: 2 (2% per attempt) detailed view 0 Submit Hint I give up Hints: 2% deduction per hint. Hints remaining: Feedback:-deduction per feedback. - 25% Part (b) What is the magnitude, in meters per second squared, of the acceleration a of the car? 25% Part (c) Write an expression for the minimum coefficient of friction between the car's tires and the road that is required in order to keep the car going in a circle in terms of the given parameters p the car going in a circle?

Explanation / Answer

Given,

d = 0.55 km

V = 25.5 m/s

a) magnitude of acceleration = v2/ (d/2)

magnitude of acceleration = 2 v2/ d

b) magnitude of acceleration = 2 x 25.52/(550)

magnitude of acceleration = 2.36 m/s2

c) for the coefficient of friction is u

u x m x g = 2 x m x v2/d

solving for u

u = 2 x v2/(d x g)

minimum coefficient of friction is 2 x v2/(d x g)

d) coefficient of friction = a/g

coefficient of friction = 2.36/9.81

coefficient of friction = 0.24

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