6:40 PM webassign.net T-Mobile LTE 0.100. (Enter the magnitude.) Find the angle
ID: 1790267 • Letter: 6
Question
6:40 PM webassign.net T-Mobile LTE 0.100. (Enter the magnitude.) Find the angle of the slope (in degrees) down which this box could move at a constant velocity. Additional Materials A freight train consists of two 8.00 x 104 kg engines and 45 cars with average masses of 4.80 x 104 kg. (For each answer, enter the magnitude.) What force (in N) must each engine exert backward on the track to accelerate the train at a rate of 6.00 x 10-2 m/s2 if the force of friction is 7.60 x 105 N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems b What is the force (in N) in the coupling between the 37th and 38th cars (this is the force each exerts on the other), assuming all cars have the same mass and that friction is evenly distributed among all of the cars and engines? Additional Materials Calculate the centripetal force (in N) on the end of a 49 m (radius) wind turbine blade that is rotating at 0.6 rev/s. Assume the mass is 6 kg. Additional Materials Modern roller coasters have vertical loops like the one shown here.Explanation / Answer
the total mass of the whole system=2(8 x 10^4) + 45 (4.80 x 10^4) =232 x 10^24 Kg
Force = ma + frictional force= (232 x 10^4 Kg)6 x 10^-2 + 7.60 x 10^5=8.992 x 10^ 5 N apprx
force for each engine= ( 8.992 x 10^ 5 N)/2=4.496 N
b)force which 37 car will exert on 38 and all cars at the back = 8 (4.80 x 10^4) (6 x 10^-2) + 8(7.60 x 10^5)
= 6.103 x 10^ 6 N apprx
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