The following is a rather unusual way to melt ice: If a block of ice at 0 o C is

Question

The following is a rather unusual way to melt ice:

If a block of ice at 0 oC is dropped from some height, it will lose gravitaional potential and gain kinetic energy. Upon hitting the groung the kinetic energy is very quickly brought to zero. (Into what form does that kinetic energy transform?)

Calculate the height that a block of ice must be dropped in order to completely melt upon impact. (You may use the following approximate conversion : 1 calorie = 4 Joules roughly.)

H =

Pls check the units he wants, J=1 kg/m2s2 and grams convert to kg. Thank you

Explanation / Answer

According to the given problem,

a) The kinetic energy is converted in to heat energy which melts the ice cube.

b) Now, Using energy convertion principle.

P.E = K.E = H = mL

where L = latent Heat of fusion of water. = 333.55 J/g ot 79.72 Ca;/g

P.E = mL

mgH = mL

gH = L

H = 34 m

I hope you understood the problem, If yes rate me! or else fell free to comment.

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