In a game of pool, the cue ball strikes another ball of the same mass and initia

Question

In a game of pool, the cue ball strikes another ball of the same mass and initially at rest. After the collision, the cue ball moves at 3.80 m/s along a line making an angle of 24.0° with its original direction of motion, and the second ball has a speed of 2.10 m/s. (a) Find the angle between the direction of motion of the second ball and the original direction of motion of the cue ball (b) Find the original speed of the cue ball m/s (c) Is kinetic energy conserved? (of the centers of mass; disregard the rotation.) O Yes O No

Explanation / Answer

Applying momentum conservation,

(m v0) + (0 ) = m (3.80 cos24i + 3.80 sin24j) + m(2.10 cos(theta)i - sin(theta)j)

along j direction,

0 = 3.80 sin24 - 2.10 sin(theta)

theta = 47.4 deg ,,,,,,,,Ans(A)

(B) along i direction,

v0 = 3.80 cos24 + 2.10 cos47.4

v0 = 4.89 m/s

(C) Ki = m (4.89^2) /2 = 11.97 m

Kf = m (3.80^2 + 2.10^2) / 2 = 9.4 m

Ans: No

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.