Kirchhoft\'s Rules and Applying Them Apply the junction nila to the unction laba

Question

Kirchhoft's Rules and Applying Them Apply the junction nila to the unction labaled with tha number at tha bottom ot tha esistor of nesistanca Ral Answer in terms of given quantities, together with the meter readings I and 1 and the current I. Learning Goal: To understand the or in8 0' both of Kirchhofs rues and how to 88 1hern to solv8 a circui: probem This probiem intrcduces Kirchhot's two niles for crcats . Krotho' 'y predon rule. The algebraic sum of the currerts ito for out any junction in the ci cut is z0. Sulmit | Te figure Emre 1)shows circuit thet ilustrates the concept trkug, which are colured red rd esbeled lop 1 d kop 2 Loop 1 is the loop uund lhe entire circuit. Incorrect; Try Again; 4 attempts remaining unctions (wtere tree or more wies meel)-lhey are at the ends of the resistor labeled Ra. The bactery supples a conatant votage V and the resistors e labeled with their eestances. The ammeters ar deal meter8 that read l'esectsely p y the loop rule to loop 2 the smaler Icop cn he n ]. m the vokage cn escross coch circuit clemem around this loop gong n the droctic Expres8 the voltege drops in terms of Vi. I,' 13, the given resistances, and any other given quentities. the row. Remember thtihe current meters ceal. The drection uf each loop rd lhe directior153ch curren! anow that you craw on yur n the oppeile cirection from your cuen amow, youranswer Tor that urent will be negstive. The cirection of any loop a even less impoant: The equation oblained tom a 8agn in front ct every term 0 , an inconsequemial change in Overal sign of the equation because it equals zam) My Answars h lip Figure 1 Incorrect; Try Again; 4 attempts remaining Part D Expres8 uhe voltarse 'ops in terms of Vha , the given 'esistances, und ully other given uentities. ' Submit My Answers Ene UR

Explanation / Answer

B)

taking the current going away from the junction as positive and current approaching the junction as negative

I1 - I2 - I3 = 0

C)

Using KVL in loop 2

- I3 R3 + I2 R2 = 0

Part D)

Using KVl in loop 1 :

I3 R3 - Vb- I1 R1 = 0

Related Questions

Navigate

• Browse (All)
• Browse K
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.