Question 2 Part 1 Suppose you have a 115 kg wooden crate resting on the floor. T

Question

Question 2 Part 1

Suppose you have a 115 kg wooden crate resting on the floor. The coefficients of the static and kinetic friction are us=0.5 and uk=0.3. If the maximum force in newtons to keep it moving horizontally is 563.5, what will is acceleration be in meters per second if you continue to exert this force once the crate starts to slip?

Question 2 Part 2

A 75.0 kg mean stand on the bathroom scale in an elevator that accelerates up with some rest 230.0 m/s in 2.00 seconds, if the scale reading in newtons is F=1860, calculate this girl reading compared with his weight.

Explanation / Answer

Part 1:

Mass of crate=115 kg

Force applied = 563.5 N

kinetic friction force on crate = 0.3*115*9.8=338.1 N

net force on crate=563.5-338.1 = 225.4 N

acceleration of crate = 225.4/115=1.96 m/s2

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