Part A An electric turntabile 0 790 m in diameter is rotating about a fixed axis

Question

Part A An electric turntabile 0 790 m in diameter is rotating about a fixed axis with an initial angular velocity of 0 200 rev/s The angular acceleration is 0 900 rev/s? Compute the angular velocity after a time of 0 190 s rev/s Submit My Answers Give Up Part B Through how many revolutions has the blade turned in this time interval? rev Submit My Answers Give Up Part c what is the tangential speed of a port on the tp of the blade at time t o 190 s ? m/s Submit My Answers Qive Up Part D What is the magnitude of the resuitlant acceleration of a point on the tp of the blade at time t0 190 s ? m/s Submit My Answers Give Up

Explanation / Answer

(A) alpha = 0.900 rev/s^2

w0 = 0.200 rev/s

wf = w0 + alpha t

w = 0.200 + (0.900 x 0.190) = 0.371 rev/s

(B) wf^2 - w0^2 = 2 a d

0.371^2 - 0.200^2 = 2(0.900)(rev)

rev = 0.054 rev

(C) v = w r

v = (0.371 x 2pi rad/s) (0.790/2) = 0.92 m/s

(d) a_t = alpha r = (0.900 x 2 pi )(0.790/2) = 2.23 m/s^2

a_r = v^2 / r = 2.14 m/s^2

a = sqrt(a_r^2 + a_t^2) = 3.09 m/s^2

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