Please show how you did the work, this question was long and confusing just tryi
ID: 1791140 • Letter: P
Question
Please show how you did the work, this question was long and confusing just trying to understand how to do it. Thank you in advance.
(17%) Problem 2: A satellite is traveling around a planet in a circular orbit with radius R. It moves in a constant speed of v 105 x 104 m/s. The mass of the planet is M-6.06 x 1024 kg. The mass of the satellite is m = 4.7 × 103 kg > 10% Part (a) Enter an expression for the kinetic energy KE of the satellite in terms of m and v Grade Summary 0% 100% 7 89 HOME Submissions Attempts remaining: 7 (3% per attempt) detailed view END VO BACKSPACE DE CLEAR give up! Hints: 0% deduction per hint. Hints remaining:- Feedback: 0% deduction per feedback. i 10% Part (b) Calculate the value of KE in Joules. as 10% Part (c) Enter an expression for the magnitude of the gravitational force F in terms of M, R, m and the gravitational constant G 10% Part (d) Enter an expression for the centripetal acceleration of the satellite ac in terms of the speed of the satellite, v, and R 10% Part (e) Enter an expression for the radius R in terms of G, M and v 10% Part (f) Calculate the value of R in meters. 10% Part (g) Enter an expression for the gravitational potential energy PE in terms of G, M, m, and R 10% Part (h) Calculate the value of PE in Joules. à 10% Part (i) Enter an expression for the total energy E of the satellite in terms of mt and v -là 10% Part (j) Calculate the value of the total energy E in Joules.Explanation / Answer
a)
KE of satellite = (0.5) m v2
b)
KE of satellite = (0.5) m v2 = (0.5) (4700) (10500)2 = 2.6 x 1011 J
c)
F = GMm/R2
d)
ac = v2/R
e)
orbital speed is given as
v = sqrt(GM/R)
R = GM/v2
f)
R = GM/v2 = (6.67 x 10-11) (6.06 x 1024) /(1.05 x 104)2 = 3.7 x 106 m
g)
PE = - GMm/R
h)
PE = - GMm/R = (6.67 x 10-11) (6.06 x 1024) (4700)/(3.7 x 106) = - 5.1 x 1011 J
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