I need help from A-D please (20%) Problem 5: Consider the circuit depicted in th

Question

I need help from A-D please

(20%) Problem 5: Consider the circuit depicted in the attached figure. The voltage source is an AC source of frequency f- 35 Hz Randomized Variables R1=194 R2= 169 C1-15 HF C2 = 3.5 F L=0.65 H C2 ©theexpertta.com 25% Part (a) Given the above circuit, write an expression for the total impedance Z for the circuit as a complex number. You may assume 25% Part (b) Given the values for resistance, inductance, and capacitance above, what is the magnitude of the phasor for the impedance z 25% Part (c) Given the values for resistance, inductance, and capacitance above, what is the phase angle of the phasor for the impedance the current is a completely real phasor Z in degrees 25% Part (d) If the voltage supplied is of the form V-Acos(m) where A= 14 V, determine the current I supplied in A at time6.7 s Grade Summary Potential Submissions Attempts remaining: 20 0% 100% sin cotan0 asinO acos0 atan) acotan) sinh(0 cosh0tanh cotanh0 tan() | | ( 78 9 % per attempt) detailed view 0 END Degrees O Radians DELCLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: Feedback: 0%-deduction per feedback.

Explanation / Answer

inductive reactance, Xl = 2*pi*f*L

capacitive impedance of C1, Xc1 = 1/(2*pi*f*C1)

capacitive impedance of C2, Xc2 = 1/(2*pi*f*C2)

total impedance = R1+R2+ i*(Xl-Xc1-Xc2) = R1+R2+ i*(2*pi*f*L - (1/(2*pi*f*C1)) - (1/(2*pi*f*C2))

part b:

using the values given.

total impedance = 363 - 4330.75 i ohms

impedance magnitude = Z= sqrt (3632 + 4330.752) = 4345.93 ohms

part c: phase angle of the phasor = tan-1(-4330.75/363)= -85.21 degrees

part d: V= 14 x cos(w*t) = 14 x cos(2 x pi x 35 x 6.7)

current=V/total impedance

= (14/4345.93)*cos(2*pi*35*t-(-85.21°))

at t= 6.7 seconds, current

= 1.543 x 10-3 A

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