605 nm) is incident on a diffraction grating that has n = 2300 lines per cm (5 %

Question

605 nm) is incident on a diffraction grating that has n = 2300 lines per cm (5 %) Problem 10: A red laser ( Randomized Variables =605 nm n = 2300 lines/cm 50% Part (a) What is the angle, in radians, that the first order maximum makes, ? Grade Summary Deductions Potential 0% 100% Submissions sinO cotan asin acos0 atan)acotan) si cosh0 tanh0 cotanh0 cosO Attempts remaining: 7 % per attempt) detailed view sinh0 0 END Degrees ORadians BACKSPACE CLEAR Submit Hint I give up! Hits: 2%-deduction per hint. Hints remaining: 4 Feedback: 2% deduction per feedback. - 50% Part (b) what is the angle of the fourth order maximum,04, in radians?

Explanation / Answer

Here ,

wavelength = 605 nm

n = 2200 lines per cm

seperation between slits , d = 1/2200 cm

d = 4.55 *10^-6 m

a) for the first order maximum

d * sin(theta) = 1 * wavelength

4.55 *10^-6* sin(theta) = 1 * 605 *10^-9

theta = 0.134 radian

the first order maximum makes is 0.134 radian

b)

for n = 4

d * sin(theta) = 4 * wavelength

4.55 *10^-6* sin(theta) = 4 * 605 *10^-9

theta = 0.561 radian

the first order maximum makes is 0.561 radian

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