Use the exact values you enter in previous answer(s) to make later calculation(s

Question

Use the exact values you enter in previous answer(s) to make later calculation(s).

A baseball player hits a baseball (m = 0.149 kg) as shown in the figure below. The ball is initially traveling horizontally with speed of 36 m/s. The batter hits a fly ball as shown, with a speed vf = 45 m/s.

(a) What are the magnitude and direction of the impulse imparted to the ball?

(b) If the ball and the bat are in contact for a time of 8.0 ms, what is the magnitude of the average force of the bat on the ball?
____________ N

Compare this answer to the weight of the ball.

= ]

(c) What is the impulse imparted to the bat?

Explanation / Answer

a)Initial velocity in x-diection=Vix=-36 m/sec

Final velocity in x-direction=Vfx=45 cos 45 m/sec

Initial velocity in y-direction=Vyi=0

Final velocity in y-direction=Vyf= 45 sin 45 m/sec

We know impulse is change in momentum.so,

Impulsex =m(Vfx-Vix)=0.149(31.82+36)=10.11 kg m/s

Impulsey =m(Vfy-Viy)=0.149(31.82-0)=4.74 kg m/s

Impulse=sqrt{Ix^2 +Iy^2}=11.17 kg m/s

Direction=arctan(Iy/Ix)=25 degree

b)Favg=Impulse/t=11.17/8*10^{-3} =1.4 kN

Favg/mg =1.4k/.149*9.8 =958.8

c)The impulse that the ball imparts to the bat is equal and opposite to the impulse the bat imparts to the ball. (This is from Newton's 3rd law.)

Manitude=10.17 kg m/s

Direction=180+25=205 degree

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