(4, A particle (charge - 40 C) moves directly toward a second particle (charge 8

Question

(4, A particle (charge - 40 C) moves directly toward a second particle (charge 80 C) which is held in a lixed position. At an instant when the distance between the two particles is 2.0 m, the kinetic energy of the moving particle is 16 J. Determine the distance separating the two particles when the moving particle is momentarily stopped. A) 0.75 m B) 0.68 m -40 x 2m 0.56 m ) 0.84 m E) 0.95 ml 24 5, Charge of uniform density 50 nC/m is distributed throughout the inside of a long nonconducting cylindrical rod (radius 5.0 cm). Determine the magnitude of thelpotential difference of point A (2.0 cm from the axis of the rod) and point B (4.0 cm from the axis). A) 2.7 V 1.7V 2t D) 2.0 V -46 K& E 2824.9 A 2 om 0.02 EAX Ca is tilted at a 45o angle to the vertical direction as shown below. The magnitude of the potential difference, VA-VB, in volts, between points A and An infinite plane of charge (insulating) thin sheet) with 555 a 4.50 m distance apart, is 2. 45 A) 4.03. B) 14.11. C) 7.06. D) 9.98. E) 11.3. 21 Page 2 of 9

Explanation / Answer

here,

charge on particle 1 , q1 = 40 uC = 4 * 10^-5 C

charge on particle 2 , q2 = 80 uC = 8 * 10^-5 C

initial sepration , r0 = 2 m

initial kinetic energy , KEi = 16 J

let the final distance between the charges be r

using conservation of energy

KEi + PEi = PEf + 0

16 + k * q1 * q2/r0 = k * q1 * q2 /r

16 + 9 * 10^9 * 4 * 10^-5 * 8 * 10^-5 /2 = 9* 10^9 * 4 * 10^-5 * 8 * 10^-5 /r

solving for r

r = 0.95 m

the final sepration between them is E)0.95 m

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