slipping. The tull downward-pointing force (called the coefficient of static fri

Question

slipping. The tull downward-pointing force (called the coefficient of static friction betwee o 11 000 N on the car. (a) What is the and the car's tires? (b) What would be the maximum speed ifno downforce acted on the car? the track the rce acted on the car? (Ans. = 0.91 the car's wing exerts 3) The skateboarder in the drawing starts dov s without 5.4 m/s. Neglect nonconservative as of the highest point reached by the skateboarder on thei tive forces, such as friction and air resistance aal peed of ed by the skateboarder on the right side of traithe heighs , v = 38 m/s) 4) A pitcher throws a 0.140-kg baseball, and it approaches the bat at a speed o does Wne D 70.0 J of work on the bal the ball after the ball leaves the bat and is 25.0 m above the point of f 40.0 m/s. The bat l in hitting it. Ignoring air resistance, determine the speed of 5) A 16-kg sled s being pulled along the horizontal snow-covered ground by ve the point of impact (Ans. 45.9 m/s) a horizontal force 0 m. Find the coefficient of

Explanation / Answer

6. centripetal acc = v^2 / R

On box:

Fnet = f = m a = m v^2 / R

and f = u N = u m g

u m g = m v^2 / r

u = v^2 / r g

u = 16^2 / (48 x 9.81) = 0.54 .....Ans

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