(9%) Problem 12: A ball with an initial velocity of 9.5 m/s and mass 2.1 kg move

Question

(9%) Problem 12: A ball with an initial velocity of 9.5 m/s and mass 2.1 kg moves at an angle 60.S° above the horizontal. The ball hits a vertical wall and bounces off so that it is moving 60.5 above the horizontal, moving in the opposite direction with the same speed. See the figure. what was the magnitude of the impulse delivered by the wall, in kilogram, meters per second? Grade Sammary Potential 100% Submissions J- tan() | 7 8 9 cos0 cotan asin0 acos0 atanO acotan inho cosh ta cotanhO sin0 Attempts remaining: O per attempt) detailed view Degrees Radians Submit Hint f give up Feedback: deduction pet feedback Hints:--deduction per hint Hith remaining:- 0

Explanation / Answer

Impulse is J = change in momentum

J = m*(v*cos(theta) - (-v*cos(theta)))

J = m*2*v*cos(theta)

J = 2.1*2*9.5*cos(60.5) = 19.65 kg m/sec

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