0/1 points | Previous Answers SercCP10 20.P.061 My Notes Ask Your Teacher The bo

Question

0/1 points | Previous Answers SercCP10 20.P.061 My Notes Ask Your Teacher The bolt of lightning depicted in the figure below passes 200 m from a 145-turn coil oriented as shown. If the current in the lightning bolt falls from 5.90 × 106 A to zero in 10.7 , what is the average voltage induced in the coil? Assume the distance to the center of the coil determines the average magnetic field at the coil's position. Treat the lightning bolt as a long, vertical wire. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kV 200 m Need Help? ReadIt Submit Answer Save Progress Practice Another Version

Explanation / Answer

Induced voltage = rate of change of magnetic flux

= [pi*r^2*(u0 i/2pi d)]/t

= [pi*0.8^2*2e-7*5.9e6/200]/10.7e-6

= 1109 V

= 1.109 kV answer

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