would you have to dive to experience an absolute pressure of 11.1 2 atm? How dee
ID: 1792599 • Letter: W
Question
would you have to dive to experience an absolute pressure of 11.1 2 atm? How deep would you have to dive to experience an absolute pressure of 5 atm? (Note that 1 atm 101.3 kPa.) t is the density of the unknown fluid in Figure 11.173 many assume that the unknown liquid is prevented from mixing with the water or displacing it in the event it is the more dense, pwater =1000 kg m-3.) 11.5 What would you estimate that the difference in average blood pressure between the top of 1.7 m tall person's head and the bot tom of their feet is? (Pblood 1060 kg m3) 11.6 Blood pressure is generally quoted in mmHg and is a gauge pressure. In this question we will convert this into SI units. Sup- pose that the systolic pressure of a particular patient is 120 mmHg and the diastolic pressure is 80 mmHg Given that 760 mmHg is equivalent to 101.3 kPa, what is the systolic and diastolic blood 8.9 cm ? 3.5 cm sure of this patient in SI units (Pa, or kPal? 11.7You wish to measure the blood pressure at the top of a pa- head but the patient is unable to lie flat. You measure the blood pressure at the bicep (i.e. level with the heart) and find that t is 140 mmHg systolic and 80 mmHg diastolic. What would you water his point is 45 cm above the measurement poin? Remember this Fiqur 11.17 Waser and an unknown ud eplaced in Figure 11.17 Water and an unknown fluid are placed in an open u-tube. this point is 45 cm above the measurement point? Remember thisExplanation / Answer
11.7
given blood pressure at biceps,
Pd ( diastolic) = 80 mmHg
Ps ( systolic) = 140 mm Hg
so pressure at the location of head which is d = 0.45 m above the measurement point will be rho*g*d Pa lesser in both cases
now P' = rho*g*d
rho = density of blood = 1060 kg/m^3
g = 9.81 m/s/s
d = 0.45 m
P' = 4679.37 Pa = 35.09815636 mm Hg
hence
pressure in head
diastolic = 80 - 35.0981 = 44.90184 mm Hg
systolic = 140 - 35.09815636 = 104.90184 mm Hg
11.10 let density of the unknown fluid be rho
then from pressure balance
1000*g*8.9 = rho*g*3.5
rho = 2542.85714 kg / m^3
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