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Question
× y0f Arkansas, L. ibiscms/mod/ibis/view.php?id-3848794 Jump to... 29/2017 06:00 PM 42/100 11/23/201709:02 PM Print 11 Caluiator Penodic Table ion 16 of 30 iversity Physios presented by Sapling Leaming in a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 14.5 m in diameter. It is found that the pilot blacks out when he is spun at 30.6 rpm (rev/mirn At what acceleration (in Si units) does the pilot black out? Number m/s Express this acceleration in terms of a multiple of g Number percent must you change the time for the pilot to make one circle? Number Hel
Explanation / Answer
1. acceleration = w^2 x R = (30.6*2*3.14/60)^2 x 14.5 = 148.7 m/sec
2. 148.7 / 9.8 = 15g
3. Acc = w1^2 x R x .82= w2^2 x R
So, w2 = sqrt(.82) = .91 of w1 = .91 x 30.6 rev/min = 27.7 rev / min
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