I\'m confused with Question 19. The answer is a, but I do not know the reason Ph

Question

I'm confused with Question 19. The answer is a, but I do not know the reason

Physics 211 Exam Spring 2012 Th e next two questions refer to the following situation: rl of mass ma-0 kg sits at the outer edge of a merry-go-round of mass M-200 kg and radiusR 25 m 0.04 kg v-700 m/s The merry-go-round is initially at rest and is free to rotate without friction. The girl shoots a gun in a horizontal direction tangent to the outer edge of the merry-g mass m 0.04 kg and a speed v= 700 m/s relative to the ground. The moment of inertia of the merry-go- round is I- MR/2. You can assume the girl is a point mass at the edge of the merry-go-round. mo=70 kg o-round as shown in the figure. The bullet has M-200 kg R=2.5m Top View 18. What is the angular velocity (o) of the girl and the merry-go-round after the gun has been sno,009 rad/s tDn½ -0.026 rad/s c.20 = 0.066 rad/s d. = 0.11 rad/s e, = 0.21 rad/s 19. The magnitude of the linear momentum of the girl right after the bullet is fired a. is less than the magnitude of the linear momentum of the bullet. is equal to the magnitude of the linear momentum of the bullet. is greater than the magnitude of the linear momentum of the bullet. c.

Explanation / Answer

The combined momentum of Girl and marry go round seat is equal to that of bullet.
So girl's momentum is equal to = momentum of bullet - momentum of seat

In other words less than bullets momentum.'

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