12. The figure shows two circular regions _ region 1 of radius Ti -25 cm and reg

Question

12. The figure shows two circular regions _ region 1 of radius Ti -25 cm and region 2 of radius r2 = 20cm-separated by 60 cm. The electric field in region 1 is 500 N/C going into the plane of the page, and that in region 2 is 700 N/C coming out of the plane of the page. The magnitudes of both fields are decreasing at a rate of 100 N/(C-s). Calculate the path integral fB-di along the path drawn in the figure; ignore the bending of the path at the crossing Note: The direction of the path integral matters (1) 3.6 x 10-16 Trn (2) 4.3 x 10-12 Trn (3) 8.2 × 10-15 Trn (4) 6.2 × 10 -19 Tm (5) 7.8 x 10-9 Tm

Explanation / Answer

given
r1 = 25 cm
r2 = 20 cm
E1= 500 N/C into the plane of the page
E2 = 700 N/C out of the plane of the page
dE/dt = -100 N / Cs

now, B.ds = ien*mu = mu*epsilon*A*dE/dt
hence
B.ds = mu*epsilon*[pi(0.25^2 + 0.20^2)]*(100)
B.ds = 3.58*10^-16
hence
option i) 3.6*10^-16 Tm

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