For Questions 24 & 25, consider the following: An isolated particle has a charge

Question

For Questions 24 & 25, consider the following: An isolated particle has a charge of 4.70x 10 C Consider a point in space 29.7cm away. 24.) What is the magnitude of the particle's electric field at this point? A.) 6.307 x 106 N/C B.) 4.795 x 10 N/C C.) 1.424 x 10 N/C D.) 4.795 × 102 N/C E.) 1.424 x 104 N/C 25.) What is the electric potential at this point? A.) 1.369 × 106 V B.) 4.795 x 10 V C.) 1.424 x 106 v D.) 4.795 x 102 v E.) 1.424 × 104 V For Questions 26-28, consider the following: The heating element of an electric oven is designed to produce 3.3 kW of heat when connected to a 240-V source. Assume the oven is ohmic. 26.) What must be the resistance of the element? A.) 13.75 B.) 72.73 C.) 17,454 D.) 0.0727 E.) 17.45 27.) How much current is drawn by the heating element? A.) 0.0573 A B.) 3.30 A C.) 17.45 A D.) 13.75 A E.) 3,301 A 28.) How much charge passes a point in the oven's power cord in 3.0 seconds? A.) 41.25 C B.) 4.58 C C.) 52.35 C D.) 5.82 C E.) 9.90 C

Explanation / Answer

24)

E = k*q/r^2

= 9*10^9*(4.7*10^-5)/0.297^2

= 4.8*10^6 N/C

25)

Electric potential ,

V = k*q/r

= 9*10^9*(4.7*10^-5)/0.297

= 1.42*10^6 V

26)

resistance, R = V^2/P = 240^2/3300

= 17.5 ohm

27)

Current, I = V/R = 240/17.5

= 13.7 A

28)

Charge passing, Q = I*t

= 13.7*(3)

= 41.1 C

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.