Verizon LTE 1:54 PM flip.tphysics.com You plan to take a trip to the moon. Since

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Verizon LTE 1:54 PM flip.tphysics.com You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the earth with enough speed to make it to the moon. Some information that will help during this problem: mearth 5.9742 x 1024 kg earth 6.3781 x 106 m mmoon - 7.36 x 102kg moon 1.7374 x 106 m dearth to moon 3.844 x 108m (center to center) G-6.67428 x 10-11 N-m2kg 'on your first attempt you leave the surface of the earth at v·5534 m/s. How far from the center of the earth will you get? Since that is not far enough, you consult a friend who calculates (correctly) the minimum speed needed as Vmin -11068 m/s. If you leave the surface of the earth at this speed, how fast will you be moving at the surface of the moon? Hint carefully write out an expression for the potential and kinetic energy of the ship on the surface of earth, and on the surface of moon. Be sure to include the gravitational potential energy of the earth even when the ship is at the surface of the moon! m/s Which of the following would change the minimum velocity needed to make it to the moon? Othe mass of the earth Othe radius of the earth Othe mass of the spaceship Below is some space to write notes on this problem

Explanation / Answer

1) Applying energy conservation,

PEi + KEi = PEf + KEf

- G M m / Rearth = - G M m / r + 0

- (6.67 x 10^-11)(5.9742 x 10^24) /(6.378 x 10^6) + 5534^2 2/ = - - (6.67 x 10^-11)(5.9742 x 10^24) / r

r = 8.445 x 10^6 m .........Ans

2) at this speed, PEi + KEi = 0

so PEf + KEf = 0

- (6.67 x 10^-11) (7.36 x 10^22) /(1.7374 x 10^6) + v^2 /2 = 0

v = 2377 m/s

3) v_min = sqrt[ 2 G M / R ]

Ans: Mass of earth

radius of earth

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