Homewwork 811 Problem 11.25-Enhanced-with Hints Problem 11.25- Enhanced-with Hin

Question

Homewwork 811 Problem 11.25-Enhanced-with Hints Problem 11.25- Enhanced-with Hints Part A A package of mass m is released from rest at a warehouse loading dock and slides down the h 2.8 m-high, frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m , from the bottom of the chute. Fiqure 1) Suppose the packages stick togother. What is thoir common speed afer the collision? Express your answer to two significant figures and include the appropriate units ·Hints You may want to review (LID pages 273-276) For help with math skills, you may want to review Solving Algebraic Equations Value Units Submit My Anewers Give Up Part B Suppose the oollision between the psckages is perfecty elastic. To what height does the package of mass m rebound? Express your answer to two significant figures and Include the appropriate units. Hints Figure 1 of 1 h Value Units Submit My Answers Give Up

Explanation / Answer

speed of block just before collision,

m gh + 0 = 0 + m v0^2 /2

v0 = sqrt(2 x 9.8 x 2.8) = 7.41 m/s

(A) Applying momentum conservation,

pi = pf

7.41m = (m + 2m) v

v = 2.5 m/s ..........Ans

(b) for elastic ,

velocity of approach = velocity of separation

v0 = V + v

V = 7.4 - v

Applying momentum conservation,

7.4 m = - m v + 2 m V

7.4 = - v + 14.8 - 2v

v = 2.5 m/s to the left

height = v^2 / 2 g = 0.31 m

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