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Which statement about the Hardy–Weinberg equilibrium is true? Select one: a. It

ID: 179372 • Letter: W

Question

Which statement about the Hardy–Weinberg equilibrium is true?

Select one:

a. It explains why dominant alleles favored by natural selection do not necessarily replace recessive alleles in a population.

b. It applies only to populations in which there is gene flow.

c. It assumes that populations are small.

d. It assumes that individuals prefer to mate with individuals with certain genotypes.

e. It predicts that the genotypic frequencies of a population will change even in the absence of evolutionary processes.

In a population of pitcher plants, 200 individuals are sampled for variation at a locus. Sixteen are heterozygous for the X1 allele, and four are homozygous for it. What is the frequency of the X1 allele?

Select one:

a. 0.04

b. 0.06

c. 0.08

d. 0.12

e. 0.16

Which condition would be most conducive to the evolution of sexual reproduction and recombination?

Select one:

a. Large population size

b. Steady temperatures

c. A very efficient DNA repair system

d. The elimination of pathogens

e. A rapidly changing environment

Darwin’s breeding of pigeons

Select one:

a. showed that breeding can produce a great deal of variation in traits.

b. provided him with a mechanism of heredity.

c. provided insight on the rate of new mutations.

d. showed that most populations have little genetic variability.

e. led him to conclude that individuals evolve.

A gene in humans has two alleles, M and N, that code for different surface proteins on red blood cells. If you know that the frequency of allele M is 0.2, according to the Hardy–Weinberg rule, the frequency of the genotype MN in the population should be

Select one:

a. 0.16.

b. 0.2.

c. 0.32.

d. 0.64.

e. 0.8.

Explanation / Answer

e) It predicts that the genotypic frequencies of a population will change even in the absence of evolutionary processes.

b)0.06

a)large population size

a) showed that breeding can produce a great deal of variation in traits.

c)0.32

p=0.2

q=1-0.2=0.8

Frequency of MN genotype is 2pq=2×0.2×0.8=0.32